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close this bookPartition Wall Making - Course: Timberwork techniques. Instruction examples for practical vocational training (Institut für Berufliche Entwicklung, 35 p.)
View the document(introduction...)
View the documentPreliminary Remarks
View the documentInstruction Example 5.1.: Calculation of the Pitch Size
View the documentInstruction Example 5.2.: Scribing of the Runners
View the documentInstruction Example 5.3.: Scribing of the Posts
View the documentInstruction Example 5.4.: Scribing of the Stiffening Transoms
View the documentInstruction Example 5.5.: Scribing of the Door Framework
View the documentInstruction Example 5.6.: Assembly and Erection of the Partition Wall

Instruction Example 5.1.: Calculation of the Pitch Size

The pitch sizes for the partition wall shown in the detailed drawing are to be determined.

Known:
Room height: 2500 mm
Length of surface covering material: 2500 mm
aadm = 600 mm
The runners are cut from 50 mm thick and 4000 mm long boards


Figure

Hand tools

None

Measuring and testing means

None

Auxiliary accessories

Paper for calculations, pencil, possibly calculator

Necessary previous knowledge

Fundamental operations, reading of drawings

Sequence of operations

Comments

1. Determine the cross section of timbers for the posts.

- Read cross section in table 1.
- Select: b = 60 mm, d = 75 mm.
- Use squared timbers of 60/80 mm2.
- d for the runner thickness = 80 mm
- b for the post width = 60 mm

2. Calculate the pitch size for wall (1).


Requ.:


Known:

b = 60 mm

Lt = 2300 mm

G1 = 4600 mm

nFa = 4

aadm = 600 mm

nTa = 2

M1 = 2500 mm


a1 = 567.5 mm


( ) indicates the steps of calculation.

3. Calculate the pitch size for wall (2)

- Since the partition walls meet at right angles, G1 for wall (2) is not 5000 mm!
The thickness d = 80 mm (runner thickness) is to be subtracted from G1 = 5000 mm!

Requ.:


Known:

- Follow steps of solution exactly!

b = 60 mm



G1 = 5000 mm - d



aadm = 600 mm


d = 80 mm

(1) G1 = 5000 mm - 80 mm

M1 = 2500 mm

G1 = 4920 mm



nTa = 2




nFa = 5!



a2 = 486 mm